In the following reaction, the product $X$ is:
$C_{6} H_{5} C H_{2} B r$ $1. M g / E t h e r - ------ \to 2. H_{3} O^{+}$ $X$

C_{6} H_{5} C H_{2} O C H_{2} C_{6} H_{5}

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C_{6} H_{5} C H_{2} O H

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C_{6} H_{5} C H_{3}

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C_{6} H_{5} C H_{2} C H_{2} C_{6} H_{5}

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Solution

The correct option is C $C_{6} H_{5} C H_{3}$
In the given reaction, the product ' $X$ ' is $C_{6} H_{5} C H_{3}$ .

Benzyl bromide reacts with $M g$ metal in ether to form benzyl magnesium bromide - a Grignard reagent.

The acid hydrolysis of benzyl magnesium bromide converts it into toluene.

Option C is correct.

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Similar questions

C_{6} H_{5} C H_{2} B r

1. M g, E t h e r - ------ \to 2. H_{3} O^{+} X

C_{6} H_{5} C H_{2} B r

C_{6} H_{5} C H_{3} + C r O_{3} + (C H_{3} C O)_{2} O \to P

C_{6} H_{6} + C H_{3} A l C l_{3} - ----- \to a n h y d r o u s H C l + C_{6} H_{5} C H_{3}

C_{6} H_{5} C H_{2} B r (i) M g, E t h e r - ------ \to (i i) H_{3} O^{+} X

^{'} X^{'}

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