In the following reaction which element is oxidized ?
$M g (s) + {C l}_{2} (g) ⟶ M g {C l}_{2} (s)$

M g

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C l_{2}

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M g^{+}

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C l^{-}

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Solution

The correct option is A $M g$
$M g (s) + {C l}_{2} (g) ⟶ M g {C l}_{2} (s)$
0 0 +2 -1
$M g$ is oxidised to ${M g}^{+ 2}$ and therefore, ${C l}_{2}$ is the oxidising agent.
${C l}_{2}$ is reduced to ${C l}^{⊖}$ and therefore, $M g$ is the reducing agent.

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