In the following reaction, which of the options acts as an oxidising agent?
$F e^{2 +} + 2 H^{+} + N O_{3}^{-} \to F e^{3 +} + N O_{2} + H_{2} O$

F e^{2 +}

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F e^{3 +}

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N O_{3}^{-}

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N O_{2}

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Solution

The correct option is C $N O_{3}^{-}$
Here, $F e^{2 +}$ is oxidised to $F e^{3 +}$ by the nitrate ion. Hence, nitrate ion $(N O_{3}^{-})$ acts as an oxidising agent.

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F e

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