Question

In the following reaction which substance is oxidised and which one is reduced?
$I_2+NaOH\to NaI{O}_3+NaI+H_{2}O$

• A. $I_2,NaOH$
• B. $NaOH,I_2$
• C. $I_2,I_2$
• D. $NaOH,NaOH$

Answer 1

The correct option is C $I_2,I_2$

$\stackrel{0}{3I_2}+6NaOH\to Na\stackrel{+5}{I}{O}_3+5Na\stackrel{-1}{I}+3H_{2}O$

We can clearly see that $I_2$ is itself oxidised as well as reduced (disproportionation).