Question

In the following reaction X and Y are respectively, $C_2{H}_2\stackrel{X}{\to }{C}_6{H}_6\stackrel{Y}{\to }{C}_6{H}_{5}S{O}_{3}H$:

• A. iron tube, heating $N{a}_{2}S{O}_4$
• B. Zn, conc. $H_{2}S{O}_4$
• C. red hot iron tube, fusing $H_{2}S{O}_4$
• D. $H_2/Pd,BaS{O}_{4}dil.H_{2}S{O}_4$

Answer 1

Answer: (C)

red hot iron tube, fusing $H_{2}S{O}_4$

Ethyne is converted to benzene by using red hot iron tube at 873K.
And conversion of benzene to benzene sulphonic acid is done by fusing $H_{2}S{O}_4$.
Hence option C is correct.