Question

In the following reaction: $xA\to yB$
$log[-\frac{d\left[A\right]}{dt}]=log[-\frac{d\left[B\right]}{dt}]+log2$
where -ve sign indicates rate of disapperance of the reactant. Thus, x : y is ____.

• A. 1 : 2
• B. 2 : 1
• C. 3 : 1
• D. 3 : 10

Answer 1

The correct option is B 2 : 1

$log[-\frac{d\left[A\right]}{dt}]$ = $log[-\frac{d\left[B\right]}{dt}]$ + $log2$

This becomes

$\frac{1}{2}\frac{d\left[A\right]}{dt}$ = $-\frac{d\left[B\right]}{dt}$

So, x =2, y =1

$x:y$ = $2:1$