In the following reaction
$X e O_{3} + 6 H^{+} + 6 F e^{2 +} ⟶ X e + 3 H_{2} O + 6 F e^{2 +}$
$e q u i v a l e n t m a s s o f X e O_{3} = \frac{m o l a r m a s s}{. . . . . . . . . .}$

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Solution

In the following reaction
$X e O_{3} + 6 H^{+} + 6 F e^{2 +} ⟶ X e + 3 H_{2} O + 6 F e^{2 +}$
$e q u i v a l e n t m a s s o f X e O_{3} = \frac{m o l a r m a s s}{6}$
The oxidation number of Xe changes from +6 (in $X e O_{3}$ ) to 0 (Xe)
$Equivalent mass = \frac{Molar mass}{Total change in the oxidation number}$ .

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