In the following reaction:
$x Z n + y H N O_{3} (d i l) ⟶ a Z n {(N O_{3})}_{2} + b H_{2} O + c N H_{4} N O_{3}$
What is the sum of the coefficients $(a + b + c)$ ?

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Solution

The balanced reaction is as follows:
$4 Z n + 10 H N O_{3} ⟶ 4 Z n {(N O_{3})}_{2} + 3 H_{2} O + N H_{4} N O_{3}$
Therefore, the sum of the co-efficients is $(a + b + c) = 4 + 3 + 1 = 8$ .

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