In the following reaction
$Z n + 2 O H^{-} + 2 H_{2} O ⟶ Z n (O H)_{4}^{2 -} + H_{2}$
The species which has been reduced is:

Z n

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O H^{-}

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H_{2} O

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none of these

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Solution

The correct option is C $H_{2} O$
Reduction may take place either by addition of electron or removal of oxygen. In he given reaction $H_{2} O$ loses one oxygen atom to form $H_{2}$ and hence is reduced

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Similar questions

Q. In the following reaction, species which has been reduced is :

Z n + 2 {O H}^{-} + 2 H_{2} O ⟶ Z n {(O H)}_{4}^{2 -} + H_{2}

Q. The salt

Z n (O H)_{2}

is involved in the following two equilibria:

Z n (O H)_{2} (s) ⇌ Z n^{2 +} (a q) + 2 O H^{-} (a q); K_{s p} = 1.3 \times 10^{- 17}

Z n (O H)_{2} (s) + 2 O H^{-} (a q) ⇌ [Z n (O H)_{4}]^{2 -} (a q); K_{c} = 0.13

Calculate the pH of the solution at which solubility is minimum.

Q. Which of the following species are oxidised and reduced in the following (unbalanced) reaction?

C + Z n O ⟶ Z n + C O

C u^{2 +} (a q) + Z n (s) \to Z n^{2 +} (a q) + C u (s)

In the above reaction which of the following is reduced?

The standard reduction potential at $25^{o} C$ of the reaction $H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}$ is $- 0 .8277 V$ . Calculate the equilibrium constant for the reaction $2 H_{2} O \to H_{3} O^{+} + O H^{-}$ at $25^{o} C$ .

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In the following reactionZn+2OH−+2H2O⟶Zn(OH)2−4+H2The species which has been reduced is:

The correct option is C H2OReduction may take place either by addition of electron or removal of oxygen. In he given reaction H2O loses one oxygen atom to form H2 and hence is reduced

In the following reaction
$Z n + 2 O H^{-} + 2 H_{2} O ⟶ Z n (O H)_{4}^{2 -} + H_{2}$
The species which has been reduced is:

The correct option is C $H_{2} O$
Reduction may take place either by addition of electron or removal of oxygen. In he given reaction $H_{2} O$ loses one oxygen atom to form $H_{2}$ and hence is reduced