In the following reactions - i PCl5-SO2- A-B ii A-MeCOOH- C-SO2-HCl iii 2C-Me2Cd- 2D-CDCl2 The compound C is-

The correct option is C Me ∥ O C Cl (i) PCl_5+SO_2→ SOCl_2 (A)+POcl_3 (B) (ii) SOCl_2+MeCOOH→ Me ∥ O C Cl (C)+SO_2+HCl ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Chlorides of Phosphorus

In the follow...

Question

In the following reactions :
$(i) P {C l}_{5} + {S O}_{2} \to A + B$
$(i i) A + M e C O O H \to C + {S O}_{2} + H C l$
$(i i i) 2 C + {M e}_{2} C d \to 2 D + C D {C l}_{2}$ The compound (C) is:

M e - C H - C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M e - C H_{2} - C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M e - C ∥ O - C l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M e - C - C l_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

(I) {M e}_{3} C - C l ⊖ O H - - \to {M e}_{3} C - O H

(I I) F_{3} C - C H | M e - C l ⊖ O H - - \to F_{3} C - C H | M e - O H

(I I I) {M e}_{3} C - C l 90 % D_{2} O + 10 % e t h e r - ----------- \to {M e}_{3} C - O D

(I V) {M e}_{3} C - C l 90 % D_{2} O + 10 % e t h e r - ----------- \to {M e}_{3} C - O H

C H_{2} - O H | C = C H | C l - O - M e | C H - C = C - C O O H

(I) {M e}_{3} C - F H_{2} O / H^{\oplus} - ---- \to {M e}_{3} C - O H

(I I) {M e}_{3} C - F ⊖ O H - - \to {M e}_{3} C - O H

(I I I) {M e}_{3} C - C l ⊖ O H - - \to {M e}_{3} C - O H

(I V) {M e}_{3} C - M e | C | M e - C l ⊖ O H - - \to {M e}_{3} C - M e | C | M e - O H

S i M e_{2} C l_{2}

∠ C l - S i - C l

∠ M e - S i - M e

∠ M e - O - M e

M e_{2} O

∠ F - O - F

F_{2} O

C - C l

C H_{3} C l

C - C l

C F_{3} C l

C - F

C H_{3} F

C - F

C H_{2} F_{2}

In the following sequence of reactions:

The product (C) is

Join BYJU'S Learning Program