In the following reactions-Me - CH - CH - Me CCl 4 Br 2- A 2 NaNH 2- B Na - liq NH 3- C The product c isA- Me - CH 2 CH 2- MeB- Me - C - C - MeCD-

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Hydrogenation of Alkynes

In the follow...

Question

In the following reactions:
$M e - C H = C H - M e B r_{2} - -- \to C C l_{4} A 2 N a N H_{2} - ---- \to B N a / l i q N H_{3} - ------ \to C$ The product (c) is

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M e - C H_{2} C H_{2} - M e

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M e - C \equiv C - M e

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M e - C H = C H - M e B r_{2} - -- \to C C l_{4} A 2 N a N H_{2} - ---- \to B N a / l i q . N H_{3} - ------ \to C

In the following sequence of reactions:

The product (C) is

M e_{3} C - O - C H_{2} C H_{3} + H I 1 mole Δ ⟶

M e_{3} C - O - C H_{2} C H_{3} + H I (1 mole) Δ - \to

i . M e - O | | C - O E t H_{3} O^{+} - -- \to

i i . M e - O | | C - O - O | | C - M e i i . L A H (e x c e s s) - --------- \to i i . H_{2} O

i i i . R - \oplus N \equiv ⊖ C H_{3} O^{+} - -- \to

i v . M e - O | | C - H P C C - -- \to

v . M e - O | | C - C | | O - M e H I O_{4} - -- \to

v i . C H_{3} - C H = C H - C H_{2} C H_{3} i . O_{3} - ---- \to i i . H_{2} O_{2}

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