In the following reactions
$M g + a i r △ \to (A) + (E) (A) + H_{2} O \to (B) C O_{2} - -- \to (C) (E) + H_{2} O \to (D) + (B)$
1 mole of (B) neutralises 2 moles of HCl.
(A) to (E) are $(A) : M g O (B) : M g (O H)_{2} (C) : M g C O_{3} (D) : N H_{3} (E) : M g_{3} N_{2}$
If true enter 1, else enter 0.

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Solution

The reactions are as shown below.
$M g + a i r △ \to M g O (A) + M g_{3} N_{2} (E)$
$M g O (A) + H_{2} O \to M g (O H)_{2} (B) C O_{2} - -- \to M g C O_{3} (C)$
$M g_{3} N_{2} (E) + H_{2} O \to (N H_{3}) (D) + M g (O H)_{2} (B)$
1 mole of (B) neutralises 2 moles of HCl.
$M g (O H)_{2} (B) + 2 H C l \to M g C l_{2} + 2 H_{2} O$
Thus, (A) to (E) are $(A) : M g O (B) : M g (O H)_{2} (C) : M g C O_{3} (D) : N H_{3} (E) : M g_{3} N_{2}$

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