Question

In the following reactions, product (A) and (B), respectively, are:

$\mathrm{NaOH}+{\mathrm{Cl}}_2\to$ (A) + side products (hot & conc.)

$\mathrm{Ca}{\left(\mathrm{OH}\right)}_2+{\mathrm{Cl}}_2\to$ (B) + side products (dry).

• A. ${\mathrm{NaClO}}_3$ and $\mathrm{Ca}{\left({\mathrm{ClO}}_3\right)}_2$
• B. $\mathrm{NaOCl}$ and $\mathrm{Ca}{\left({\mathrm{ClO}}_3\right)}_2$
• C. $\mathrm{NaOCl}$ and $\mathrm{Ca}{\left(\mathrm{OCl}\right)}_2$
• D. ${\mathrm{NaClO}}_3$ and $\mathrm{Ca}{\left(\mathrm{OCl}\right)}_2$

Answer 1

Answer: (C), (D)

${\mathrm{NaClO}}_3$ and $\mathrm{Ca}{\left(\mathrm{OCl}\right)}_2$

Solution: The correct option is A.

• Sodium hydroxide combines with chlorine to form sodium chloride as a major product because of the high electropositive nature of sodium and high electronegative nature of chlorine

$6\mathrm{NaOH}+3{\mathrm{Cl}}_2\to 5\mathrm{NaCl}+{\mathrm{NaClO}}_3+3{\mathrm{H}}_2\mathrm{O}$

• Calcium hydroxide reacts with chlorine to form calcium chloride as a major product because of the high electropositive nature of calcium and high electronegative nature of chlorine.

$2\mathrm{Ca}{\left(\mathrm{OH}\right)}_2+{\mathrm{Cl}}_2\to \mathrm{Ca}{\left(\mathrm{OCl}\right)}_2+{\mathrm{CaCl}}_2+{\mathrm{H}}_2\mathrm{O}$

• All the chemical combinations are occurred in simple whole number ratio and according to the law of conservation of mass.