In the following redox reaction Cr2O2-7-Fe2- Fe3-Cr3- 1 mole of Cr2O2-7 oxidises-

The correct option is C 6 moles of Fe^2+ Oxidation half reaction #160; 6Fe^+2→ 6Fe^+3+6e^ Reduction half reaction Cr_2O_7^2 +14H^++6e^ ...

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Standard XII

Chemistry

Potassium Dichromate

In the follow...

Question

In the following redox reaction $C r_{2} O_{7}^{2 -} + F e^{2 +} ⟶ F e^{3 +} + C r^{3 +} 1$ mole of $C r_{2} O_{7}^{2 -}$ oxidises?

1

mole of

F e^{2 +}

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3

moles of

F e^{2 +}

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4

moles of

F e^{2 +}

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6

moles of

F e^{2 +}

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Solution

The correct option is C $6$ moles of $F e^{2 +}$
Oxidation half reaction $6 F e^{+ 2} \to 6 F e^{+ 3} + 6 e^{-}$
Reduction half reaction $C r_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 C r^{+ 3} + 7 H_{2} O$
Reaction is
$6 F e^{2 +} + C r_{2} O_{7}^{2 -} + 14 H^{+} \to 6 F e^{+ 3} + 2 C r^{+ 3} + 7 H_{2} O$

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Similar questions

Q. In the following redox reaction

C r_{2} O_{7}^{2 -} + F e^{2 +} \to F e^{3 +} + C r^{3 +}

One mole of

C r_{2} O_{7}^{2 -}

oxidises?

Q. For the redox reaction

C r_{2} O_{7}^{2 -} + F e^{2 +} + H^{+} \to C r^{3 +} + F e^{3 +} + H_{2} O

The correct coefficients of the following for the balanced reaction are

Q. For a redox reaction,

F e S_{2} + K M n O_{4} \to {F e}_{2} O_{3} + S_{8} + {M n}^{+ 2}

if 1 mole of

S_{8}

is produced then calculate moles of

K M n O_{4}

consumed

Q. Determine the potential for the cell:

P t | F e^{2}, F e^{3 +} | | C r_{2} O_{7}^{2 +}, C r^{3 +}, H^{+} | P t

in which

[F e^{2 +}]

and

[F e^{3 +}]

are

0.5 M

and

0.75 M

respectively and

[C r_{2} O_{7}^{2 -}], [C r^{3 +}]

and

[H^{+}]

are

2 M, 4 M

and

1 M

respectively, Given:

F e^{3 +} + e^{-} \to F e^{2 +}; E^{\circ} = 0.770 v o l t

14 H^{+} + 6 e^{-} + C r_{2} O_{7}^{2 -} \to 2 C r^{3 +}, 7 H_{2} O; E^{\circ} = 1.35 v o l t

Q. A given amount of

{F e}^{2 +}

is oxidised by

x

moles of

M n O_{4}^{-}

in acidic medium. Calculate number of moles of

{C r}_{2} O_{7}^{2 -}

required to oxidise same amount in

{F e}^{2 +}

in acidic medium if

x = 5

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In the following redox reaction Cr2O2−7+Fe2+⟶Fe3++Cr3+ 1 mole of Cr2O2−7 oxidises?

The correct option is C 6 moles of Fe2+Oxidation half reaction 6Fe+2→6Fe+3+6e−Reduction half reaction Cr2O2−7+14H++6e−→2Cr+3+7H2OReaction is6Fe2++Cr2O2−7+14H+→6Fe+3+2Cr+3+7H2O

In the following redox reaction $C r_{2} O_{7}^{2 -} + F e^{2 +} ⟶ F e^{3 +} + C r^{3 +} 1$ mole of $C r_{2} O_{7}^{2 -}$ oxidises?