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Question

In the following redox reaction Cr2O27+Fe2+Fe3++Cr3+ One mole of Cr2O27 oxidises?

A
6 mole of Fe2+
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B
1 mole of Fe2+
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C
4 mole of Fe2+
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D
3 mole of Fe2+
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Solution

The correct option is A 6 mole of Fe2+
Oxidation half reaction 6Fe+26Fe+3+6e
Reduction half reaction Cr2O27+14H++6e2Cr+3+7H2O
The full ionic equation may be obtained by adding the half-reaction for potassium dichromate to the half-reaction for the reducing agent
6Fe2++Cr2O27+14H+6Fe+3+2Cr+3+7H2O
Thus, One mole of Cr2O27 oxidises 6 mole of Fe2+

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