In the following redox reaction:
$Z n (s) + N O_{3}^{-} (a q) + H^{+} (a q) ⟶ {Z n}^{2 +} (a q) + {N H}_{4}^{+} (a q)$
$Z n (s)$ and $N O_{3}^{-} (a q)$ respectively are, respectively :

oxidant and reductant

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reductant and oxidant

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both oxidant

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both reductant

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Solution

The correct option is B reductant and oxidant
$Z n (s) + N O_{3}^{-} (a q) + H^{+} (a q) ⟶ {Z n}^{2 +} (a q) + {N H}_{4}^{+} (a q)$
0 +5 +2 -3
$Z n ⟶ {Z n}^{2 +}$
$Z n$ is oxidised. Hence, it is reducing agent (reductant).
$N + 5 O_{3}^{-} ⟶ {N H}_{4}^{+} - 3$
$N O_{3}^{-}$ is reduced. Hence, it is oxidising agent (oxidant).

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