In the following sequence of reaction:
$C H_{2} C H_{2} C H_{2} B r K O H (a l c) - ----- \to (A) H B r - -- \to (B) K O H (a q) - ----- \to (C)$ .

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Solution

$C H_{3} C H_{2} C H_{2} B r K O H (a l c) - ------------ \to (a s a l c h o l i c s o - H_{2} O) C H_{3} - C H = C H_{2}$
$↓ H B r$
$C H_{3} - C H | B r - C H_{3}$
$↓ K O H (a q)$
$C H_{3} - C H | O H - C H_{3}$

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