the product (C) is : \( H _{3} C - Br \stackrel{ KCN }{\longrightarrow} Ether \underset{ Ci LiAlH _{4} O ^{+}}{\longrightarrow} \)
A
Ethyl alcohol
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B
Actaldehyde
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C
Methane
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D
Aceton
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Solution
The correct option is A Ethyl alcohol Alkyl bromide undergoes nulceophilic substitution reaction with KCN followed by hydrolysis of CN to give COOH and further get reduced to OH group in presence of LiAlH4.