In the following sequence of reactions, products A, B, C, D and E are formed.
The structure of product (A) is:

H_{2} C = C H_{2}

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H C \equiv C H

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M e - \equiv - H

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M e - \equiv - M e

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Solution

The correct option is C $M e - \equiv - H$
Structure of magnesium carbide $M g_{2} C_{3}$ is $M g = C = C = C = M g$ .

When it undergoes hydrolysis, it forms $M g (O H)_{2}$ with propyne $(A)$ gas.

$M g = C = C = C = M g + 4 H_{2} O \to 2 M g (O H)_{2} + C H_{3} - C \equiv C H$

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Similar questions

In the following sequence of reactions:

The product (C) is

M e - C H = C H - M e B r_{2} - -- \to C C l_{4} A 2 N a N H_{2} - ---- \to B N a / l i q N H_{3} - ------ \to C

M e - C H = C H - M e B r_{2} - -- \to C C l_{4} A 2 N a N H_{2} - ---- \to B N a / l i q . N H_{3} - ------ \to C

M e_{3} C - O - C H_{2} C H_{3} + H I 1 mole Δ ⟶

M e - C l + N H_{3}

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