In the following sequence of reactions. The compound $C$ formed will be:

$C H - C | H N H_{2} - C H_{3} H N O_{2} - --- \to A O x i d a t i o n - ----- \to B (i) C H_{3} M g l - ------ \to (i i) H^{+} / H_{2} O C$

butanol-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

butanol-2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2-methyl propanol-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1, 1-dimethylethanol

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 1, 1-dimethylethanol
The end product (C) is 1, 1-dimethylethanol.
Isopropyl amine reacts with nitrous acid to form isopropyl alcohol. On oxidation acetone is obtained which then reacts with methyl magnesium iodide (a grignard reagent) followed by acid hydrolysis to give 1, 1-dimethylethanol..

Suggest Corrections

Similar questions

C H_{3} - C H_{2} - C H_{2} - C l (a) p r o p y l c h l o r i d e) A l c . K O H - ----- \to C H_{3} - C H = C H_{2} (P r o p e n e b)

C H_{3} - C H_{2} - C O O H + B r_{2} P B r_{3} - -- \to C H_{3} - C | B r H - C O O H

H_{2} O, C H_{3} N H_{2} - -------- \to

C H_{3} - C | N H_{2} H - C O O H

C H_{3} - C H = C H - C H_{3} O_{3} - \to A H_{2} O - - \to Z n B .

The compound (B) formed in the following sequence of reactions

$C H_{3} C H_{2} C H_{2} O H P C l_{5} - -- \to (A) a l c . K O H - ---- \to (B)$

C H_{3} - C H_{3} | C H - O | | C - O H + C H_{3} - N H_{2} \to A - \to Δ B L i A l H_{4} (e x c e s s) - --- \to^{'} C^{'}

Join BYJU'S Learning Program