In the following sequence of reactions, the end product is:

$C H_{3} C \equiv C H H_{2} S O_{4} / H g^{2 +} - ------- \to H_{2} O / 60^{o} A C H_{3} M g C l - ----- \to H_{2} O B$

acetone

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tertiary butyl alcohol

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secondary propyl alcohol

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ethyl alcohol

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Solution

The correct option is D tertiary butyl alcohol
A is acetone which is formed after oxymercuartion-demercuartion reaction on acetylene. The reaction is as follows:

$C H_{3} C \equiv C H H_{2} S O_{4} / H g^{2 +} - ------- \to H_{2} O / 60^{o} C H_{3} C O C H_{3} C H_{3} M g C l - ----- \to H_{2} O (C H_{3})_{3} C O H$

Hence, a tertiary alcohol is formed.

Option B is correct.

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Similar questions

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In the following sequence of reactions, the end product is:CH3C≡CHH2SO4/Hg2+−−−−−−−−→H2O/60oACH3MgCl−−−−−−→H2OB

In the following sequence of reactions, the end product is:

$C H_{3} C \equiv C H H_{2} S O_{4} / H g^{2 +} - ------- \to H_{2} O / 60^{o} A C H_{3} M g C l - ----- \to H_{2} O B$