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Question

In the following series of numbers find out how many times 1, 3 and 7 are together 7 being in the middle and 1 and 3 on either side of 7
2 9 7 3 1 7 3 7 7 1 3 3 1 7 3 8 5 7 1 3 7 7 1 7 3 9 0 6

A
3
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B
4
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C
5
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D
More than 5
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Solution

The correct option is A 3
We have to find out how many times 1,3 and 7 beign the middle and 1 and 3 on either side of 7.

Basically we have to find

173 and

371

Lets underline these number in the above sequence and count them.

the number 173 comes thrice

hence, option A is the correct answer.

1447056_346049_ans_efe12a1b71c4422a865cad14cb7dccaa.PNG

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