Question

In the following set of aromatic compounds the correct order of reactivity toward Friedel-Crafts alkylation is:

• A. i > ii > iii > iv
• B. ii > iv > iii > i
• C. iv > ii > iii > i
• D. iii > i > iv > ii

Answer 1

Answer: (C)

iv > ii > iii > i

The correct order of reactivity toward Friedel-Crafts alkylation is $iv>ii>iii>i$
Friedel-Crafts alkylation is electrophilic aromatic substitution reaction.
Hence, the option (C) is the correct answer.
In $iv$, the electron releasing $methoxy$ group increases the electron density on $benzene$ ring and increases the reactivity toward Friedel-Crafts alkylation.
In $i$, the electron withdrawing $nitro$ group decreases the electron density on $benzene$ ring and decreases the reactivity toward Friedel-Crafts alkylation.