Question

In the following set of reactions:
$A\to 2C+D3A\to 5E+2F$
15 moles of A was consumed. It was found that 10 moles of C were formed. Find the amount of E formed in moles.

Answer 1

$A\to 2C+D3A\to 5E+2F$
In reaction (i),
10 moles of C was formed.
As per the reaction,
2 moles of C is produced by 1 mole of A.
10 moles of C will be produced by 5 moles of A.
Amount of A left for $2^{nd}$ reaction,
$=15-5=10mol$
In reaction (ii),
3 moles of A produce 5 moles of E.
10 moles of A will produce,
= $\frac{5}{3}\times 10=16.67mol$