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Question

In the following set of reactions:
A2C+D3A5E+2F
15 moles of A was consumed. It was found that 10 moles of C were formed. Find the amount of E formed.

A
10.25 mol
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B
16.67 mol
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C
13.87 mol
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D
19.68 mol
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Solution

The correct option is B 16.67 mol
A2C+D3A5E+2F
In reaction (i),
10 moles of C was formed.
As per the reaction,
2 moles of C is produced by 1 mole of A.
10 moles of C will be produced by 5 moles of A.
Amount of A left for 2nd reaction,
=155=10 mol
In reaction (ii),
3 moles of A produce 5 moles of E.
10 moles of A will produce,
= 53×10=16.67 mol

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