Question

In the following set of reactions:
$A\to 2C+D3A\to 5E+2F$
15 moles of A was consumed. It was found that 10 moles of C were formed. Find the amount of E formed.

• A. 10.25 mol
• B. 16.67 mol
• C. 13.87 mol
• D. 19.68 mol

Answer 1

The correct option is B 16.67 mol

$A\to 2C+D3A\to 5E+2F$
In reaction (i),
10 moles of C was formed.
As per the reaction,
2 moles of C is produced by 1 mole of A.
10 moles of C will be produced by 5 moles of A.
Amount of A left for $2^{nd}$ reaction,
$=15-5=10mol$
In reaction (ii),
3 moles of A produce 5 moles of E.
10 moles of A will produce,
= $\frac{5}{3}\times 10=16.67mol$