In the following the correct bond order sequence is:

O_{2}^{+} > O_{2}^{-} > O_{2}^{2 -} > O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

O_{2}^{2 -} > O_{2}^{+} > O_{2}^{-} > O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

O_{2} > O_{2}^{-} > O_{2}^{2 -} > O_{2}^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$
Electronic configuration and bond order of the given species:
$O_{2} : σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{1} = π^{} 2 p_{y}^{1}$
$B . O . = 2$

$O_{2}^{+} : σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{1}$
$B . O . = 2.5$

$O_{2}^{-} : σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{1}$
$B . O . = 1.5$

$O_{2}^{2 -} : σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{2} = π^{*} 2 p_{y}^{2}$
$B . O . = 1.0$

$∴$ Correct bond order sequence is,

$O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$

Suggest Corrections

Similar questions

π

H_{2} S_{2} O_{6}

H_{2} S O_{3}

H_{2} S_{2} O_{5}

Join BYJU'S Learning Program