In the following unbalanced redox reaction:
${C u}_{3} P + {C r}_{2} O_{7}^{2 -} ⟶ {C u}^{2 +} + H_{3} P O_{4} + {C r}^{3 +}$
Equivalent weight of $H_{3} P O_{4}$ is $\frac{M}{x}$ . The value of $x$ is :

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Solution

${C u}_{3} P + {C r}_{2} O_{7}^{2 -} ⟶ {C u}^{2 +} + H_{3} P O_{4} + {C r}^{3 +}$
-3 +5
$equivalent weight$ $= \frac{Molar mass}{Valency} = \frac{M}{8}$ .

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Similar questions

C r_{2} O_{7}^{2 -}^{+} C r^{3 +}

Find the equivalent weight of

C r_{2} O_{7}^{2 -}

in the above redox half reaction.
(Given the molar mass of

C r_{2} O_{7}^{2 -}

M g / m o l

)

{C r}_{2} O_{7}^{2 -}

changes to

{C r}^{3 +}

in acidic medium. Thus, molecular weight of

{C r}_{2} O_{7}^{2 -} = x \times

equivalent weight. What is the value of

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{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} ⟶ {F e}^{3 +} + {C r}^{3 +}

1 mol of

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Q. In the following reaction (unbalanced), equivalent weight of

A s_{2} S_{3}

is related to molecular weight

M

by M/x.

{A s}_{2} S_{3} + H^{+} + {N O}_{3}^{-} ⟶ N O + H_{2} O + A s O_{4}^{3 -} + S O_{4}^{2 -}

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value of x is _______.

Which of the following statement does not hold true for the following reaction?
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In the following unbalanced redox reaction:Cu3P+Cr2O2−7⟶Cu2++H3PO4+Cr3+Equivalent weight of H3PO4 is Mx. The value of x is :

Cu3P+Cr2O2−7⟶Cu2++H3PO4+Cr3+ -3 +5 equivalent weight =Molar massValency=M8.

In the following unbalanced redox reaction:
${C u}_{3} P + {C r}_{2} O_{7}^{2 -} ⟶ {C u}^{2 +} + H_{3} P O_{4} + {C r}^{3 +}$
Equivalent weight of $H_{3} P O_{4}$ is $\frac{M}{x}$ . The value of $x$ is :

${C u}_{3} P + {C r}_{2} O_{7}^{2 -} ⟶ {C u}^{2 +} + H_{3} P O_{4} + {C r}^{3 +}$
-3 +5
$equivalent weight$ $= \frac{Molar mass}{Valency} = \frac{M}{8}$ .