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Equivalent Mass

In the follow...

Question

In the following unbalanced redox reaction,
$H_{2} S (g) + S O_{2} (g) ⟶ S (s) + H_{2} O$
total number of equivalents of $S O_{2}$ is :

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Solution

$2 H_{2} S ↑ - 2 (g) + S ↑ + 4 O_{2} (g) ⟶ 3 S 0 (s) + 2 H_{2} O (l)$
Change in oxidation number $= 4$ units
Thus, number of equivalents of $S O_{2} = 4$

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