In the following velocity-time graph of a body. the distance and displacement travelled by the body in 5 seconds in meter will be

75, 115

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110, 70

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45, 75

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95, 55

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Solution

The correct option is C $110, 70$
Distance $=$ area under graph $=$ area of five parts under graph $= \frac{1}{2} \times 2 \times 20 + 2 \times 20 + 1 \times 20 + \frac{1}{2} \times 1 \times 20 + \frac{1}{2} \times 1 \times 40$
Distance $= 20 + 40 + 20 + 10 + 20 = 110 m$
Displacement $=$ area above $x$ axis $-$ area under $x$ axis $= 90 - 20 = 70 m$
Hence,
option $(B)$ is correct answer.

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In the following velocity-time graph of a body. the distance and displacement travelled by the body in 5 seconds in meter will be

The correct option is C 110,70Distance= area under graph = area of five parts under graph =12×2×20+2×20+1×20+12×1×20+12×1×40Distance=20+40+20+10+20=110mDisplacement = area above x axis −area under x axis =90−20=70m Hence,option (B) is correct answer.