In the following velocity time graph of a body the distance traveled by the body and it's displacement during $5$ second in meter will be

75, 75

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110, 70

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110, 110

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110, 40

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Solution

The correct option is B 110, 70
$A_{1} = \frac{1}{2} \times 60 \times 20 = 60$
$A_{2} = \frac{1}{2} \times 3 \times 20 = 30$
$A_{3} = \frac{1}{2} \times 1 \times 40 = 20$
Distance $= A_{1} + A_{2} + A_{3} = 60 + 30 + 20 = 110 m$
Displacement $= A_{1} + A_{2} - A_{3} = 60 + 30 - 20 = 70 m$

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In the following velocity time graph of a body the distance traveled by the body and it's displacement during 5 second in meter will be

The correct option is B 110, 70A1=12×60×20=60A2=12×3×20=30A3=12×1×40=20Distance =A1+A2+A3=60+30+20=110mDisplacement =A1+A2−A3=60+30−20=70m

In the following velocity time graph of a body the distance traveled by the body and it's displacement during $5$ second in meter will be

The correct option is B 110, 70
$A_{1} = \frac{1}{2} \times 60 \times 20 = 60$
$A_{2} = \frac{1}{2} \times 3 \times 20 = 30$
$A_{3} = \frac{1}{2} \times 1 \times 40 = 20$
Distance $= A_{1} + A_{2} + A_{3} = 60 + 30 + 20 = 110 m$
Displacement $= A_{1} + A_{2} - A_{3} = 60 + 30 - 20 = 70 m$