Question

In the formation of $N{H}_3\left(g\right)$ by the reaction $N_2\left(g\right)+3H_2\left(g\right)\to 2N{H}_3\left(g\right)$, the rate of disappearance of $H_2$ is $6\times {10}^{2}Mmi{n}^{-1}$. The rate of appearance of $N{H}_3$ is

• A. $6.67\times {10}^{-4}M{s}^{-1}$
• B. $4\times {10}^{-2}M{s}^{-1}$
• C. $1\times {10}^{-2}Mmi{n}^{-1}$
• D. $8\times {10}^{-2}Mmi{n}^{-1}$

Answer 1

The correct option is A $6.67\times {10}^{-4}M{s}^{-1}$

Rate = $\frac{d\left[n_2\right]}{dt}=\frac{-1}{3}\frac{d\left[H_2\right]}{dt}=\frac{1}{2}\frac{d\left[N{H}_3\right]}{dt}$
$\frac{d\left[N{H}_3\right]}{dt}=\frac{-2}{3}\times \frac{d\left[N_2\right]}{dt}$
$=\frac{2}{3}\times 6\times {10}^{-2}$
$=4\times {10}^{-2}M$
$=\frac{4\times {10}^{-2}}{60}m{s}^{-1}$
$=0.667\times {10}^{-3}$
$=6.67\times {10}^{-4}M{s}^{-1}$