In the formation of $S O_{2}$ and $S O_{3}$ , the ratio of the weights of oxygen, which combines with $10$ kg of sulphur is:

1 : 1

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3 : 2

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2 : 3

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3 : 4

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Solution

The correct option is A $2 : 3$
The reaction is given below:
$S$ + $O_{2}$ $\to$ $S O_{2}$

32 gm or 32 kg of sulphur reacts with 32 gm or 32 kg of oxygen gas.

Thus, 10 kg of sulhur reacts with 10 kg of oxygen gas.

$2 S$ + 3 $O_{2}$ $\to$ 2 $S O_{3}$

64 gm or 64 kg of sulphur reacts with 96 gm or 96 kg of oxygen gas

Thus, 10 kg of sulphur reacts with 15 kg of oxygen.

$∴$ Weight of oxygen required are 10 Kg and 15 Kg respectively.

The ration will be 10 : 15 or 2:3.

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Similar questions

S O_{2}

S O_{3}

2 : 3

O_{2} \to S O_{3}

S O_{2} + 1 / 2 O_{2} \to S O_{3}

S O_{2}

S + \frac{3}{2} O_{2} \to {S O}_{3} + 2 x

{S O}_{2} + \frac{1}{2} O_{2} \to {S O}_{3} + y

{S O}_{2}

In the reaction

$S + \frac{3}{2} O_{2} \to S O_{3} + 2 x k J$ and $S O_{2} + \frac{1}{2} O_{2} \to S O_{3} + y k J$

Heat of formation of $S O_{2}$ is

S + \frac{3}{2} O_{2} \to S O_{3} + 2 x k c a l

S O_{2} + \frac{1}{2} O_{2} \to S O_{3} + y k c a l

S O_{2}

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