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Question

In the formula of brown ring complex [Fe(H2O)5(NO)]SO4, the magnetic moment is 3.87 B.M. The oxidation state of Fe and number of unpaired electrons present respectively are :

A
1+,3
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B
2+,3
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C
3+,3
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D
3+,5
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Solution

The correct option is A 1+,3
Magnetic moment μ=n(n+2) , where n is no. of unpaired electron.
Here μ=3.87 so n=3.
So electronic configuration of Fe d7,Fe+.

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