You visited us 1 times! Enjoying our articles? Unlock Full Access!

Wave Speed expression

In the formul...

Question

In the formula $P = \frac{n R T}{V - b} e^{- \frac{a}{R T V}}$ . Find the dimensions of $a$ and $b$ where $P = p r e s s u r e, n = n u m b e r o f m o l e s, T = t e m p e r a t u r e, V = v o l u m e a n d R = u n i v e r s a l g a s c o n s t a n t$ .

[a] = M^{1} L^{5} T^{- 2} m o l^{- 1}, [b] = L^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[a] = M^{1} L^{3} T^{- 2} m o l^{- 1}, [b] = L^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[a] = M^{1} L^{5} T^{- 2} m o l^{- 1}, [b] = L^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $[a] = M^{1} L^{5} T^{- 2} m o l^{- 1}, [b] = L^{3}$
$[b] = [v] = [L^{3}]$ dimensions of $\frac{a}{R T V} = [M^{\circ} L^{\circ} T \circ]$
$\Rightarrow [a] = d i m e n s i o n s o f R T V$
$= [\begin{matrix} \frac{M^{1} L^{2} T^{- 2}}{k \times m o l} \end{matrix}] \times [k] \times [L^{3}] = [M^{1} L^{5} T^{- 2} m o l^{- 1}]$

Suggest Corrections

Similar questions

(P - \frac{a}{V^{2}}) (V - b) = n R T

n

(P + \frac{a}{V^{2}}) (V - b) = n R T

P

V

T

R

a, b

P V

P = \frac{n R T}{V} e^{- \frac{\propto}{R T V}}

\propto

a

b

(P + \frac{a}{V^{2}}) (V - b) = R T

P

V

R

T

(P + \frac{a}{V^{2}}) (V - b) = n R T

P, V, R, T

n

a

b

\frac{b}{a}

Join BYJU'S Learning Program