In the Freundlich-s adsorption isotherm equation- logxm - log K - 1n log p- the value of n is-

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Fruendlich Isotherm

In the Freund...

Question

In the Freundlich's adsorption isotherm equation, $log \frac{x}{m} = log K + (\frac{1}{n}) log p$ , the value of $n$ is:

any value from

0

1

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a negative integer

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a positive integer

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a positive or a negative fractional number

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Solution

The correct option is B a positive integer
In the Freundlich's adsorption isotherm equation, $n$ is an integer, the value of which is one or greater than one (in other words, value of $n$ is a positive integer).

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In the Freundlich's adsorption isotherm equation, logxm=logK+(1n)logp, the value of n is:

The correct option is B a positive integerIn the Freundlich's adsorption isotherm equation, n is an integer, the value of which is one or greater than one (in other words, value of n is a positive integer).

In the Freundlich's adsorption isotherm equation, $log \frac{x}{m} = log K + (\frac{1}{n}) log p$ , the value of $n$ is:

The correct option is B a positive integer
In the Freundlich's adsorption isotherm equation, $n$ is an integer, the value of which is one or greater than one (in other words, value of $n$ is a positive integer).