In the galvanic cell :
$Z n / Z n^{2 +} (C_{1}) | | C u^{2 +} (C_{2}) / C u$
$E_{c e l l} - E_{c e l l}^{o} = + 0.0591 V$ . The value of $\frac{C_{1}}{C_{2}}$ at $298 K$ is:

10^{- 1}

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10^{2}

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10^{- 2}

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Solution

The correct option is D $10^{- 2}$
$E_{c e l l} - E_{c e l l}^{o} = + 0.0591 V$
$E_{c e l l} = E_{c e l l}^{o} + 0.0591 V$
But
$E_{c e l l} = E_{c e l l}^{o} - \frac{0.0591}{n} l o g \frac{C_{1}}{C_{2}}$
Hence,
$+ 0.0591 = - \frac{0.0591}{2} l o g \frac{C_{1}}{C_{2}}$
$l o g \frac{C_{1}}{C_{2}} = - 2$
$\frac{C_{1}}{C_{2}} = 10^{- 2}$
Hence, option (C) is the correct answer.

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Similar questions

C u^{2 +} (C_{1}) (a q .) + Z n (s) \to Z n^{2 +} (C_{2}) (a q .) + C u (s)

(△ G)

T = 298 K)

C u (s) | C u^{2 +} (1.0 M) | | A g^{+} (1.0 M) | A g (s) E_{c e l l}^{\circ} = 0.46 V

Z n (s) | Z n^{2 +} (1.0 M) | | C u^{2 +} (1.0 M) | C u (s) E_{c e l l}^{\circ} = 1.10 V

E_{c e l l}

Z n | Z n^{2 +} (0.1 M) | | A g^{+} (1.0 M | A g

298 K

Z n (s) + {C u}^{2 +} (0.1 M) ⟶ {Z n}^{2 +} (1 M) + C u (s)

E_{c e l l}^{o}

1.10 V

E_{c e l l}

(2.303 \frac{R T}{F} = 0.0591)

$Z n | Z n^{2 +} (C_{1}) | | Z n^{2 +} (C_{2}) | Z n$ ,

for this cell $Δ G$ is negative if:

Z n | {Z n}^{2 +} (C_{1}) ∥ {Z n}^{2 +} (C_{2}) | Z n

Δ G

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