In the gas phase reaction C2H4 - H2- C2H6 the equilibrium constant can be expressed in units of-

The correct option is B Ltr. Mole^ 1 The equilibrium reaction is C_2H_4 + H_2⇔ C_2H_6 .The units of the equilibrium constant are (moles/lit)^Δ n ...

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Standard XII

Chemistry

Characteristics of Chemical Equilibrium

In the gas ph...

Question

In the gas phase reaction $C_{2} H_{4} + H_{2} \Leftrightarrow C_{2} H_{6}$ the equilibrium constant can be expressed in units of:

L t r^{- 1} m o l e^{- 1}

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L t r . M o l e^{- 1}

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M o l e^{2} L t r .^{- 2}

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M o l e l t r^{- 1}

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Solution

The correct option is B $L t r . M o l e^{- 1}$
The equilibrium reaction is $C_{2} H_{4} + H_{2} \Leftrightarrow C_{2} H_{6}$ .
The units of the equilibrium constant are $(m o l e s / l i t)^{Δ n}$ .
Here, $Δ n$ is the difference in the total number of moles of products and reactants.
$Δ n = 1 - (1 + 1) = - 1$ .
Hence the unit of the equilibrium constant becomes $(m o l e s / l i t)^{- 1} = L t r . M o l e^{- 1}$ .

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For the gas phase reaction $C_{2} H_{4} + H_{2} ⇌ C_{2} H_{6},$ $Δ H$ = -32.7kcal carried out in a vessel, the equilibrium concentration of $C_{2} H_{4}$ can be increased by -

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In the gas phase reaction C2H4+H2⇔C2H6 the equilibrium constant can be expressed in units of:

In the gas phase reaction $C_{2} H_{4} + H_{2} \Leftrightarrow C_{2} H_{6}$ the equilibrium constant can be expressed in units of: