In the gaseous equilibrium $A + 2 B ⇌ C + H e a t$ , the forward reaction is favoured :

Low P, High T

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Low P, Low T

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High P, Low T

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High P, High T

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Solution

The correct option is B High P, Low T
$A + 2 B ⇌ C + H e a t$
The equation shows, that it is exothermic reaction. Since the heat is released in the reaction, so the reaction is favoured in forward direction at low temperature.
$Δ n = 1 - (2 + 1) = - 2$
Since the number of moles decreases, $∴$ the forward reaction is favoured at high pressure.

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