In the given $A B$ and $C D$ bisect each other at $O$ .State the three pairs of equal parts in two triangles $A O C$ and $B O D$

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Solution

From the given figure,
1. $O C = O D$
2. $O A = O B$
$∠ C O A = 180^{o} - ∠ C O B . . . . . (1)$ (linear pair)
$∠ D O B = 180^{o} - ∠ C O B . . . . . . . (2)$ (linear pair)
3. $∠ C O A = ∠ D O B$ from $(1) & (2)$

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In the givenAB and CD bisect each other at O.State the three pairs of equal parts in two triangles AOC and BOD

From the given figure,1.OC=OD2. OA=OB ∠COA=180o−∠COB.....(1) (linear pair)∠DOB=180o−∠COB.......(2) (linear pair)3. ∠COA=∠DOB from (1)&(2)

In the given $A B$ and $C D$ bisect each other at $O$ .State the three pairs of equal parts in two triangles $A O C$ and $B O D$

From the given figure,
1. $O C = O D$
2. $O A = O B$
$∠ C O A = 180^{o} - ∠ C O B . . . . . (1)$ (linear pair)
$∠ D O B = 180^{o} - ∠ C O B . . . . . . . (2)$ (linear pair)
3. $∠ C O A = ∠ D O B$ from $(1) & (2)$