Question

In the given $AD=BE$ and $\angle DAB=\angle EBA$. Then $\Delta DAB\cong \Delta EBA$ by AAS postulate.

• A. True
• B. False

Answer 1

The correct option is B

False

In $\Delta DAB$ and $\Delta EBA$

(ii) $AD=BE$ ………(given)

(ii) $\angle DAB=\angle EBA$ ……….(given)

(iii) $AB=AB$ ………(common)

Hence $\Delta DAB\cong \Delta EBA$ by SAS postulate.

Therefore the given statement is false.