In the given arrangement, if hanging mass will be changed by $4 %$ , then percentage change in the wave speed in string will be

2 %

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8 %

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3 %

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4 %

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Solution

The correct option is A $2 %$
Wave Speed $(v) = \sqrt{\frac{T}{μ}} = \sqrt{\frac{m g}{μ}}$
So $\frac{Δ v}{v} = \frac{1}{2} \frac{Δ m}{m}$
Given $\frac{Δ m}{m} \times 100 = 4$
Percentage change in $v = 2 %$

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In the given arrangement, if hanging mass will be changed by 4%, then percentage change in the wave speed in string will be

The correct option is A 2%Wave Speed(v)=√Tμ=√mgμSo Δvv=12ΔmmGiven Δmm×100=4Percentage change in v=2%

In the given arrangement, if hanging mass will be changed by $4 %$ , then percentage change in the wave speed in string will be

The correct option is A $2 %$
Wave Speed $(v) = \sqrt{\frac{T}{μ}} = \sqrt{\frac{m g}{μ}}$
So $\frac{Δ v}{v} = \frac{1}{2} \frac{Δ m}{m}$
Given $\frac{Δ m}{m} \times 100 = 4$
Percentage change in $v = 2 %$