In the given arrangement, the normal force applied by block on the ground is

m g

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m g - F cos θ

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m g + F cos θ

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F cos θ

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Solution

The correct option is B $m g - F cos θ$
Free body diagram:-
Refer image,
$N + F cos θ = m g$
$N = m g - F cos θ$
$↓$
Normal force
The correct option is B.

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In the given arrangement, the normal force applied by block on the ground is

The correct option is B mg−FcosθFree body diagram:-Refer image,N+Fcosθ=mgN=mg−Fcosθ ↓Normal forceThe correct option is B.

The correct option is B $m g - F cos θ$
Free body diagram:-
Refer image,
$N + F cos θ = m g$
$N = m g - F cos θ$
$↓$
Normal force
The correct option is B.