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Question

In the given balanced reaction, aAsO33+bI2+cH2OdAsO34+eI+2H+, the value of a, b, c, d & e respectively are :

A
1, 2, 1, 1, 4
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B
1, 2, 2, 1, 4
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C
2, 1, 2, 1, 1
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D
1, 1, 1, 1, 2
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Solution

The correct option is C 1, 1, 1, 1, 2
The unbalanced chemical equation is
AsO33+I2AsO34+I
Balance all atoms except H and O.
AsO33+I2AsO34+2I
The oxidation number of As changes from +3 to +5. The net change in the oxidation number is 2.
The oxidation number of iodine changes from 0 to -1. The net change in the oxidation number per I atom is 1.
Total change in the oxidation number for 2 I atoms is 2.
Thus, the increase in the oxidation number is equal to the decrease in the oxidation number.
Balance O atoms by adding 1 water molecule to LHS.
AsO33+I2+H2OAsO34+2I
Balance H atoms by adding 2 H+ to the RHS.
AsO33+I2+H2OAsO34+2I+2H+
This is the balanced chemical equation.
Thus, he value of a, b, c, d & e respectively are 1, 1, 1, 1, 2.

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