Question

In the given circle, with AB as diameter, find the value of 'x'.

[ 1 mark]

Answer 1

$\angle ACB={90}^{\circ }$ --- (Angle in a semi circle is ${90}^{\circ }$)
$\angle BCD={90}^{\circ }-{30}^{\circ }={60}^{\circ }$
$\angle DAB=\angle DCB={60}^{\circ }$ --- (angles in the same segment are equal)

$\therefore x=\angle DAB={60}^{\circ }$ [1 mark]