In the given circuit all ammeters are ideal. Then choose correct statement.
A
Reading of A2 = Reading of A5
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B
Reading of A2 and reading of A4 both are zero.
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C
Reading of A1 is 5 amp
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D
Reading of A1=52 times reading of A3.
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Solution
The correct options are B Reading of A2 and reading of A4 both are zero. C Reading of A1 is 5 amp D Reading of A1=52 times reading of A3. Using KVL −I1+10−10−2I1=0