Question

In the given circuit ammeter and voltmeter are ideal and battery of $6V$ has internal resistance $1\Omega$ . The reading of voltmeter and ammeter is:

• A. $zero,\frac{4}{3}$
• B. $\frac{4}{3}V,zero$
• C. $6A,0.1A$
• D. $3.6V,0.6A$

Answer 1

The correct option is D $3.6V,0.6A$

The resultant circuit can be drawn as,

The total resistance of the circuit=$3+3+3+1$

$=10\Omega$

Using Ohm's Law, $V-IR$

$\to 6=I10$

$⟹I=0.6A$

$⟹$ The reading of Ammeter will be $=0.6A$

Now, for voltmeter across resistance $R^{\prime }$

and $R^{\prime }=3+3=6\Omega$

Using ohm's law, $⟹V=IR$

$=0.6\times 6=3.6V$

Reading of voltmeter=$3.6V$