Question

In the given circuit calculate potential difference between A and B

Answer 1

By KVL

$V_A+3I_1+4-3I_2=V_B$

$KVL\left(1\right)$

$2-3I_1-2I_1=0$

$5I_1=2$

$I_1=\frac{2}{5}=0.4$

$KVl\left(2\right)$

$4-3I_2-5I_2=0$

$8I_2=4$

$I_2=0.5$

$V_A-V_B=4-3I_1+3I_2$

$=4-3\left(I_1-I_2\right)$

$V_A-V_B=4-3\left(-0.1\right)=4.3$

We get, $V_A-V=4.3$