In the given circuit diagram, in the steady state, the current through the battery and the charge on the Capacitor respectively are.
At steady state, current through capacitor is zero, because capacitor get fully charged.
Current through resistor 4Ω gets zero.
Total resistance
1Rtotal=1R1+1R2+1R3=11+12+13=116
Rtotal=611Ω
I=VRtotal=6611=11A
Fully charge capacitor Q=CV=0.5×10−6×6=3μC
Current is 11A and charge 3μC