Question

In the given circuit diagram, the currents, $I_1=-0.3A,I_4=0.8A$ and $I_5=0.4A$, are flowing as shown. The currents $I_2,I_3$ and $I_6$ respectively, are

• A. $-0.4A,0.4A,1.1$
• B. $1.1A,-0.4A,0.4$
• C. $1.1A,0.4A,0.4A$
• D. $0.4A,1.1A,0.4A$

Answer 1

The correct option is C $1.1A,0.4A,0.4A$

From Kirchhoff's current law, total incoming current at a junction must equal the total outgoing current from that junction

At junction $S$

By $KCL$, total outgoing current $=$ total incoming current

$I_3+I_5=I_4$

$I_3=I_4-I_5$

Given, $I_4=0.8A,I_5=0.4A$

$\Rightarrow I_3=0.8-0.4=0.4A$

Hence, value of $I_3$ is $0.4A$.



At junction $P$

Given, $I_5=0.4A$
From $KCL,I_5=I_6=0.4A$

Hence, value of $I_6$ is $0.4A$.

At junction $Q$
From $KCL,I_2+I_1=I_6+I_3$

Given, $I_1$ is equal to $-0.3A$

$I_2=0.4A+0.4A+0.3A=1.1A$

Hence, value of $I_2$ is $1.1A$

Hence, option (a) is crrect.